| « | November 2007 | » | ||||
 |
||||||
| S | M | T | W | T | F | S |
| 1 | 2 | 3 | ||||
| 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| 11 | 12 | 13 | 14 | 15 | 16 | 17 |
| 18 | 19 | 20 | 21 | 22 | 23 | 24 |
| 25 | 26 | 27 | 28 | 29 | 30 | |
Please answer the following question.
1) Will the acceleration of a car be the same when it travels around a sharp curve at 60 km/hr as when it travels around a gentle curve at the same speed? Explain.
Thursday, 29 November 2007 - 4:49 PM EST
Name: "Danielle Gronlie"No, the average speed will be different. When the car goes around the sharp curve it will have traveled less distance making that average speed less than when the car will travel around a gentle curve which has a greater distance.
Thursday, 29 November 2007 - 5:17 PM EST
Name: "Steph Capoferri"
No, the average speed will be different. When you go around a sharp curve your distance that you travel is less, when the curve is more gradual you cover more distance. It is the same idea as the radius of a circle and its affect on speed.
Thursday, 29 November 2007 - 6:28 PM EST
Name: "Nicole Antonik"No, the average speed will be different. The distance traveled in a sharp curve is less than the distance traveled in a gradual/ gental curve; therefore, the average speed will be different and much greater for the gradual curve than the sharp.
Thursday, 29 November 2007 - 7:24 PM EST
Name: "Allison Davis "
No. The acceleration of the car when it travels around a sharp curve will be greater than the acceleration when it travels around a gentle curve at the same speed. Using the equation a=v2/r, since the velocities are the same, the situation with the smaller radius, which is the sharp curve, has the greater acceleration.
by the way, the 2 in the equation is supposed to mean "squared"
Thursday, 29 November 2007 - 8:13 PM EST
Name: "Rob Vucelich"No. The acceleration will be greater on the sharp turn because it has a smaller radious. Because everyone knows acceleration equals velocity squared over radius.
Thursday, 29 November 2007 - 8:50 PM EST
Name: "Greg Lieb"The acceleration would not be the same. This is like a ball swinging in a circle on a string. The closer the ball gets to the center of the circle, it's speed would be different than if it were farther away because it's radius would change. In this case, the car would move faster around a gentle turn compared to a sharp curve for the same reason as the ball, the distance traveled is different.
Thursday, 29 November 2007 - 9:45 PM EST
Name: "Ryan Carson"No, the acceleration of the car around a sharp curve will be larger than a gentle curve. As in the equation a=v2/r, if the car is traveling at the same speed around both curves, than the curve on a circle with a smaller radius, the sharp curve, will yield greater acceleration.
Thursday, 29 November 2007 - 10:16 PM EST
Name: "Kevin Dougherty"
The accelerations will be different. The car traveling along the sharper curve will have a greater acceleration. Looking at the equation, ac = V2/r: if the velocities are the same, the object with the larger radius will have the lesser acceleration, and the object with the smaller radius will have the greater acceleration. If velocity remains constant, acceleration increases as radius decreases.
Thursday, 29 November 2007 - 10:18 PM EST
Name: "Kevin Doc"To the first three that responded... I thought we were asked about acceleration, not average speed?
Thursday, 29 November 2007 - 10:36 PM EST
Name: "Joe Noce"The accelerations would not be the same because the radius of the circles would differ. Since the radius is inversely related to acceleration, the sharp curve with a smaller radius will yield a higher acceleration.
Thursday, 29 November 2007 - 10:40 PM EST
Name: "Joe Noce"I wasn't sure if we were still suppose to respond to someone else's comment. So just in case, I agree with what Allison said about the acceleration in relation to the radius and how they would differ. If we weren't suppose to, I am sorry.
Thursday, 29 November 2007 - 10:46 PM EST
Name: "Jonathan Madary"
The accelerations would be different. The sharper curve would have a smaller radius than the gentle curve, which will have the car accelerating quicker on a sharp curve than a gentle curve because of the equation a=v^2/r. Since both cars will be going the same speed, the sharper curve will have the greater acceleration.
Thursday, 29 November 2007 - 10:52 PM EST
Name: "Meredith Withelder"The accelerations would be different because the sharp curve would yield a higher acceleration assuming the velocity remained constant. The smoother curve therefore, has a smaller acceleration. The equation Ac = v^2 / r suggests that as the velocity remains constant and the radius varies, the centripital acceleration is inversely proportional to that of the radius. This means that as the radius decreases the acceleration increases, and vice versa.
Friday, 30 November 2007 - 9:58 AM EST
Name: "Derek Krajek"The accelerations would be different. Using the acceleration equation a=vv/r, where velocity is 60 km/h for each situation, the tighter curve (smaller radius) will have a larger acceleration than the gentler curve (larger radius). Let's say that the radius of the tight curve is 2 km, while the radius of the gentle curve is 4 km. a=vv/r=(60*60)/(2)=1800m/s/s. a=vv/r=(60*60)/(4)=900.
Friday, 30 November 2007 - 12:42 PM EST
Name: "Joe Duffy"The centripetal acceleration of the car will be much greater when traveling around the sharp curve because the radius of the circle it is traveling around is shorter. Therefore, because the velocity is the same, the centripetal acceleration will be greater around the sharp curve.
