Thursday, 29 November 2007 - 5:21 PM EST

I dont think my last post posted

If the two light waves were exactly 180 degrees out of phase, the viewing screen would appear opposite of what a normal viewing screen would look like.  The dark and light spots would be reversed.  For example, the point exactly between the two slits would be a point of destructive interference instead of constructive.

Since violet light has a shorter wavelength than red light, it must be compressed more to have a greater angle of refraction.  This means that the index of refraction for violet light must be greater than that of red light. 

Thursday, 29 November 2007 - 8:38 PM EST

As Matthew said, if the waves were to enter the slit 180 degrees out of phase, then you would get the opposite result on the screen then if the waves were in phase.  Rather than having constructive interference and a light spot in between the slits on the screen, you would have destructive interference and a dark spot.

Violet light has a shorter wavelength than red light.  Therefore, the index of refraction of glass is greater for violet light than it is for red light.  Since the wavelength is shorter and the angle of refraction is greater than red light, the index of refraction has to be greater.

Thursday, 29 November 2007 - 10:00 PM EST

A. If the two light waves were 180 degress out of phase you would get an opposite viewing screen from what a normal one looks like. The dark and light spots would be switched. Points that used to be constructive would now be destructive and vice versa.A

Thursday, 29 November 2007 - 10:43 PM EST

I agree with what everyone else has already stated. If the light entered each slit 180 degrees out of phase, then the interferences would be reversed, for instance a dark spot happening where there would normally be a light spot.

Also, since the wavelength of violet light is shorter than that of red light, it must also be compressed more to have a larger angle of refraction. Therefore, the index of refraction for violet light is greater than that of red light.

Thursday, 29 November 2007 - 11:11 PM EST

Like Bob said, I agree with what's already been said.

 If the waves enter the slits out of phase by 180 degrees, the dark and light spots would be flip-flopped. Constructive interference would no longer occur between the slits as that would be replaced with destructive interference and vice versa.

 The index of refraction is greater for shorter wavelengths. By the same token, higher wavelengths have lesser indexes of refraction. Therefore, violet light would have a greater index of refraction then red light because its wavelength is shorter.

Thursday, 29 November 2007 - 11:32 PM EST

1.      I cannot really find any argument with what any one else has said in the blog. I think that if a piece of glass were placed in front of the two slits and were 180 degrees out of phase. Then I think that the experiment would be the opposite from what it normally would be when there is no glass in front of the slits. What I mean by this is that where a light spot would normally appear there would instead be a dark spot. Then where there would normally be a dark spot there would be a light spot. This also implies that the constructive interference, which cause the light spots, and the destructive interference that causes the dark spots in this case would switch.

2.      The wavelength for a violet light wave is shorter then the wavelength of a red light wave. Since both of the light waves enter in at the same angle on the prism. It only makes sense that the index of refraction for a red light wave will be less then that of the index of refraction for a violet light wave. Since we know that the angle of refraction for the violet light wave is greater then that of the red light wave then that means that the index of refraction for the violet light wave has to be greater to cause this to happen.

Thursday, 29 November 2007 - 11:50 PM EST

1.) 180 degrees out of phase means opposite of what normally happens. Meaning that where there are normally constructive interferences there will now be destructive interferences or where there were normally light spots there are now dark spots.

2. When a normal white light hits the prism the voilet light deviates much more from the expected refrection then the red therefore the violet light has the greater index of refrection.

Thursday, 29 November 2007 - 11:55 PM EST

My answer is the same as what everyone else has been saying.  The light and dark spots would be reversed.

Again my answer is the same as eeryone elses.  You have a greater angle of refraction for shorter wavelengths and you have a higher index of refraction when you have a greater angle of refraction so Violet light would fit both of these situations because it has a shorter wavelength than red light.

Friday, 30 November 2007 - 6:38 AM EST

1)  If a thin piece of glass were placed in front of the lower slit in a double slit experiment so that the two waes enter the slits 180 degrees out of pahse then the interference pattern on the screen would the exact opposite what the normal one looks like through the viewing screen.  This means that the light and dark spots that are viewed would be switched/reversed.  Therefore, points that are light and have constructive interfernce would be dark and have destructive interference.

2)  Since with know that violet has a shorter wavelength than red, this indicates that inorder for violet to have a greater angle of refraction it has to be compressed.  Which concludes in letting us know that the index of refraction for violet light is greater than the index of regraction of red light.

Friday, 30 November 2007 - 7:22 PM EST

1) Since the lights are out of phase, the destructive interferences would switch places with the constructive ones, so a destructive dark spot would be at the center instead of a light spot

2) Since the violet beam has a greater wavelength, a higher index of refraction would be needed to bend the light so it was incident at the same angle as red light

Basically, what everyone agreed on already